Well, there are various variables used to determine the equation of the tangent line to the curve at a particular point: The slope of a tangent line; On the curve, where the tangent line is passing;

tangent\:of\:f(x)=\frac{1}{x^2},\:(-1,\:1) tangent\:of\:f(x)=x^3+2x,\:\:x=0; tangent\:of\:f(x)=4x^2-4x+1,\:\:x=1; tangent\:of\:y=e^{-x}\cdot \ln(x),\:(1,0) tangent\:of\:f(x)=\sin (3x),\:(\frac{\pi

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The slope of the tangent line at this point of tangency, say “ a ”, is the instantaneous rate of change at x=a (which we can get by taking the derivative of the curve and plugging in “ a ” for “ x

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The equation of the tangent line at depends on the derivative at that point and the function value. The derivative at that point of is using the Power Rule which means The derivative is zero, so

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Formula for the equation of the tangent line. You’ll see it written different ways, but in general the formula for the equation of the tangent line is???y=f(a)+f'(a)(x-a)??? When a problem asks you to find the equation of the

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Find the Tangent Line at the Point y = 7x x−1,(2,14) y = 7 x x - 1, ( 2, 14)

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