Substitute the equation of the parabola into the distance formula to get the square root of a quartic to minimise. This is quadratic in x^2, so complete the square to find the

Find a point on a parabola that's closest to another point Question: Find the point on the parabola $3x^2+4x-8$ that is closest to the point $(-2,-3)$. My plan for this problem was

Answer (1 of 11): > Find the point on the parabola y^2=2x that is closest to the point (1,4). How can I approach this? Rewrite the parabola as: x = \frac {y^2}{2

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