The standard form of the equation of a hyperbola with center \left (h,k\right) (h,k) and transverse axis parallel to the x -axis is \frac { {\left (x-h\right)}^ {2}} { {a}^ {2}}-\frac { {\left (y-k\right)}^ {2}}

Dividing both sides by 16, we get . Therefore, final equation of hyperbola in standard form is \frac { (x-1)^2} {16}-\frac { (y-2)^2} {4}=1 Advertisement mazeem757 Answer:

Find the standard form of the equation of the hyperbola, (b) find the center, vertices, foci, and asymptotes of the hyperbola, and (c) sketch the hyperbola. Use a graphing utility to verify

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Find the standard form of the equation of the hyperbola with the given characteristics. Vertices: (0,5); foci: (0, +6) Need Help? Read It 6. [-/1 Points) DETAILS LARPCALC10 10.4.013. Find the

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