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Arithmetic progression with the first term 5 and the common difference d = (-2-5) = -7. The n-th term is = + d* (n-1). In your case = 5 + (-7)* (n-1). (1) To find , substitute n= 50 into the formula

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Find the 50th term of this arithmetic sequence: 2, 5, 8, 11, 1 See answer Advertisement maxidicakre is waiting for your help. Add your answer and earn points. epicman00900 It adds 3

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- the mean value of arithmetic series is x̅; - standard deviation of any arithmetic progression is σ. Then: a n = a 1 + d(n - 1) S = [n(a 1 +a n)]/2. x̅ = (a 1 +a n) /2. σ = |d|*√((n-1)*(n+1)/12) Example